Damn you, algebra

[mdklatt]

A system of equations in (x, y, z):

A = x - y
B = x - z
C = z - y

There are three equations, but none of them contain all three variables so I'm screwed, right?

[RacerX]

no.

[Fugue]

FermacerX

[mdklatt]

no.

No, I'm not screwed? Please explain. I keep trying to solve the bastards (by hand) and keep getting identities or the variable cancel each other out.

[FirstandGoal]

Too many years and too many beers to help ya there

[mdklatt]

N/M

[yermom]

B=A-C?

[proud gonzo]

what are you solving for?

C + B = A

[Stanley1]

True?

[mdklatt]

My coefficient matrix has a zero diagonal in it. I think that's bad.

[yermom]

i'm not sure. but yeah, it might be

[achiro]

D=All of the above

[Howzit]

42

[mdklatt]

what are you solving for?

(x, y, z)

I think this system is underdetermined.

[Mjcpr]

Examine Your Zipper!!!!


Hahahhaahah!!

[Howzit]

I did determine that A = A, B = B, and C = C if that's any help.

[1stTimeCaller]

a combination of A and B can be C, if done correctly.

[Harry Beanbag]

When in doubt, the answer is always C.

[KABOOKIE]

A system of equations in (x, y, z):

A = x - y
B = x - z
C = z - y

There are three equations, but none of them contain all three variables so I'm screwed, right?

I count 6 variables. But, if you want terms of ABC then sure you can solve this.

[FirstandGoal]

Is thread making anybody else think of the Jackson 5?