BermudaSooner
10/22/2012, 10:49 AM
So obviously KSU needs to lose and OU does not control our own destiny. Given the likelihood of KSU losing 2 of the following games: (Tech, OSU, TCU, Baylor, Texas), the other scenario is a 3 way tie. I thought that would be with WVU, but when they lost to Tech, that screwed that up. But now, if Tech were to beat KSU this weekend, we would then need Tech to win out to have a 3 way tie. In the event of a 3 way tie, following are the criteria:
Tiebreaker Procedures
Courtesy: Big12Sports.com
Release: 07/31/2008
Effective June 2011
The following procedure will determine the Big 12 Conference representative to the Bowl Championship Series in the event of a first-place tie:
If two teams are tied, the winner of the game between the two tied teams shall be the representative.
If three or more teams are tied, steps 1 through 4 will be followed until a determination is made. Once a team has been eliminated from a multi-team comparison, it is dropped from further comparisons. If only two teams remain tied after any step, the winner of the game between the two tied teams shall be the representative.
1. The records of the three teams will be compared against each other
2. The records of the three teams will be compared against the next highest placed teams in the conference
3. The highest ranked team in the first Bowl Championship Series Poll following the completion of Big 12 regular season conference play shall be the representative, unless the two highest ranked tied teams are ranked within one spot of the other in the BCS poll. In this case, the head-to-head results of the top two highest ranked tied teams shall determine the representative in the Bowl Championship Series.
4. The representative will be chosen by draw.
So if there was a 3 way tie, OU would have to be 2 spots ahead of KSU in the BCS--otherwise KSU still goes.
Now the really interesting scenario is OU finishes #2 in the BCS and KSU finishes #3. KSU would be the representative for the BCS---but I'm guessing this means they get the Fiesta bowl---which is just fine because OU would be going to Miami for all of the marbles....I think. Not exactly sure what "representative in the BCS" means unless it just means who goes to the Fiesta.
Tiebreaker Procedures
Courtesy: Big12Sports.com
Release: 07/31/2008
Effective June 2011
The following procedure will determine the Big 12 Conference representative to the Bowl Championship Series in the event of a first-place tie:
If two teams are tied, the winner of the game between the two tied teams shall be the representative.
If three or more teams are tied, steps 1 through 4 will be followed until a determination is made. Once a team has been eliminated from a multi-team comparison, it is dropped from further comparisons. If only two teams remain tied after any step, the winner of the game between the two tied teams shall be the representative.
1. The records of the three teams will be compared against each other
2. The records of the three teams will be compared against the next highest placed teams in the conference
3. The highest ranked team in the first Bowl Championship Series Poll following the completion of Big 12 regular season conference play shall be the representative, unless the two highest ranked tied teams are ranked within one spot of the other in the BCS poll. In this case, the head-to-head results of the top two highest ranked tied teams shall determine the representative in the Bowl Championship Series.
4. The representative will be chosen by draw.
So if there was a 3 way tie, OU would have to be 2 spots ahead of KSU in the BCS--otherwise KSU still goes.
Now the really interesting scenario is OU finishes #2 in the BCS and KSU finishes #3. KSU would be the representative for the BCS---but I'm guessing this means they get the Fiesta bowl---which is just fine because OU would be going to Miami for all of the marbles....I think. Not exactly sure what "representative in the BCS" means unless it just means who goes to the Fiesta.